Class 11 · Physics · 5 questions
Name: ____________________ Date: ____________
In simple harmonic motion the acceleration is proportional to:
The time period of a mass m on a spring of constant k is:
A pendulum has period 2 s. What is its length? (g = pi squared, about 9.87 m/s2)
At the mean position of SHM, the speed is:
Resonance occurs when the driving frequency equals the:
1. A, 2. A, 3. A, 4. D, 5. B
a = -omega2 x.
T = 2 pi times the square root of (m / k).
T = 2 pi sqrt(L / g). With g = pi2, T = 2 sqrt(L), so L = 1 m.
Speed is greatest at the mean position and zero at the extremes.
When the two match, the amplitude becomes large.