نویں جماعت · ریاضی · 6 سوالات
نام: ____________________ تاریخ: ____________
Solve 3x + 5 = 20.
Solve 2x - 7 = 9.
Solve x/4 = 7.
Solve the inequality 2x + 1 > 7.
When both sides of an inequality are multiplied by a negative number, the inequality sign:
The sum of two consecutive numbers is 41. What is the smaller number?
1. B, 2. D, 3. A, 4. C, 5. D, 6. D
3x = 15, so x = 5.
2x = 16, so x = 8.
Multiply both sides by 4: x = 28.
2x > 6, so x > 3.
Multiplying or dividing by a negative number reverses the inequality sign.
x + (x + 1) = 41 gives x = 20.